Find the equation of the line whose x-intercept is 6 and y-intercept is -4.

Since, x-intercept = 6 and y-intercept = -4, it means line will intersect x-axis at (6, 0) and y-axis at (0, -4).

The equation of line passing through two points is given by two point formula i.e.,

$y - y$1 = \dfrac{y2 - y1}{x2 - x1}(x - x1)

Putting values in above equation we get,

$\Rightarrow y - 0 = \dfrac{-4 - 0}{0 - 6}(x - 6) \\[1em] \Rightarrow y = \dfrac{4}{6}(x - 6) \\[1em] \Rightarrow y = \dfrac{2}{3}(x - 6) \\[1em] \Rightarrow 3y = 2(x - 6) \\[1em] \Rightarrow 3y = 2x - 12 \\[1em] \Rightarrow 2x - 3y = 12.$

Hence, the equation of the line is 2x - 3y = 12.