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Mathematics

Find the equation of the line through the points A(-1, 3) and B(0, 2). Hence, show that the points A, B and C(1, 1) are collinear.

Straight Line Eq

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Answer

By formula,

Slope = y2y1x2x1\dfrac{y2 - y1}{x2 - x1}

Substituting values we get,

Slope of AB = 230(1)=11\dfrac{2 - 3}{0 - (-1)} = \dfrac{-1}{1} = -1.

By point-slope form,

Equation of AB is :

⇒ y - y1 = m(x - x1)

⇒ y - 3 = -1[x - (-1)]

⇒ y - 3 = -1(x + 1)

⇒ y - 3 = -x - 1

⇒ x + y = -1 + 3

⇒ x + y = 2.

Slope of BC = 1210=11\dfrac{1 - 2}{1 - 0} = \dfrac{-1}{1} = -1.

Since, slope of AB = slope of BC.

Hence, proved that A, B and C are collinear and equation of AB is x + y = 2.

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