Find the equation of the line passing through the point (2, -5) and making an intercept of -3 on the y-axis.

Let the equation be y = mx + c, where c is the y-intercept and m is the slope.

Since, the line passes through the point (2, -5) hence, the point must satisfy the equation,

⇒ -5 = 2m - 3
⇒ -5 + 3 = 2m
⇒ 2m = -2
⇒ m = -1.

Putting value of m and c in y = mx + c,

⇒ y = -x - 3
⇒ x + y + 3 = 0.

Hence, the equation of the line is x + y + 3 = 0.