Find the equation of a straight line whose inclination is 60° and which passes through the point (0, -3).

Given inclination = θ = 60°.

m = tan θ = tan 60° = $\sqrt{3}$.

Let the equation of line be y = mx + c.

Since, the line passes through point (0, -3) hence, it must satisfy the equation. Putting point and m in the equation,

⇒ -3 = $\sqrt{3} \times 0$ + c
⇒ c = -3.

So, the equation of line whose slope = $\sqrt{3}$ and y-intercept = -3 is,

y = $\sqrt{3}$x - 3 or $\sqrt{3}x - y - 3 = 0.$

Hence, the equation of straight line is $\sqrt{3}x - y - 3 = 0.$