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Mathematics

Find the equation of the straight line passing through (-1, 2) and whose slope is 25.\dfrac{2}{5}.

Straight Line Eq

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Answer

The equation of line with slope m and passing through point (x1, y1) is given by

y - y1 = m(x - x1)

Putting values we get,

y2=25(x(1))5(y2)=2(x+1)5y10=2x+22x5y+2+10=02x5y+12=0.\Rightarrow y - 2 = \dfrac{2}{5}(x - (-1)) \\[1em] \Rightarrow 5(y - 2) = 2(x + 1) \\[1em] \Rightarrow 5y - 10 = 2x + 2 \\[1em] \Rightarrow 2x - 5y + 2 + 10 = 0 \\[1em] \Rightarrow 2x - 5y + 12 = 0.

Hence, the equation of the line is 2x - 5y + 12 = 0.

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