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Mathematics

Find the distance between the following pair of points :

(a, b), (-a, -b)

Coordinate Geometry

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Answer

By distance formula,

d = (x2x1)2+(y2y1)2\sqrt{(x2 - x1)^2 + (y2 - y1)^2}

Let P(x1, y1) and Q(x2, y2) be the given points

Co-ordinates of P = (a, b)

Co-ordinates of Q = (-a, -b)

PQ=(aa)2+(bb)2=(2a)2+(2b)2=4a2+4b2=4(a2+b2)=2a2+b2.PQ = \sqrt{(-a - a)^2 + (-b - b)^2} \\[1em] = \sqrt{(-2a)^2 + (-2b)^2} \\[1em] = \sqrt{4a^2 + 4b^2}\\[1em] = \sqrt{4(a^2 + b^2)} \\[1em] = 2\sqrt{a^2 + b^2}.

Hence, distance between (a, b) and (-a, -b) = 2a2+b22\sqrt{a^2 + b^2} units.

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