Mathematics
Calculate the mean, by step-deviation method, for the frequency distribution given below :
Class-interval | Frequency |
---|---|
0-5 | 6 |
5-10 | 14 |
10-15 | 30 |
15-20 | 48 |
20-25 | 32 |
25-30 | 16 |
30-35 | 10 |
35-40 | 4 |
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Answer
i = Class size = 5.
In table below,
t =
Class-interval | Frequency (f) | Mid-value (x) | d = x - A | t | f × t |
---|---|---|---|---|---|
0-5 | 6 | 2.5 | -20 | -4 | -24 |
5-10 | 14 | 7.5 | -15 | -3 | -42 |
10-15 | 30 | 12.5 | -10 | -2 | -60 |
15-20 | 48 | 17.5 | -5 | -1 | -48 |
20-25 | 32 | A = 22.5 | 0 | 0 | 0 |
25-30 | 16 | 27.5 | 5 | 1 | 16 |
30-35 | 10 | 32.5 | 10 | 2 | 20 |
35-40 | 4 | 37.5 | 15 | 3 | 12 |
Total | Σf = 160 | Σft = -126 |
By formula,
Mean = A +
= 22.5 +
= 22.5 -
= 22.5 - 3.9375
= 18.56
Hence, mean = 18.56
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