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Mathematics

A largest possible sphere is carved out from a solid wooden cube of side 7 cm. Find :

(i) the volume of sphere

(ii) the percentage of wood wasted in the process.

(Take π = 227\dfrac{22}{7})

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Answer

(i) Largest sphere can have diameter = side of cube = 7 cm.

Radius of sphere (r) = Diameter2=72\dfrac{\text{Diameter}}{2} = \dfrac{7}{2} = 3.5 cm

By formula,

Volume of sphere=43πr3=43×227×(3.5)3=43×22×0.5×(3.5)2=5393=17923 cm3.\text{Volume of sphere} = \dfrac{4}{3}πr^3 \\[1em] = \dfrac{4}{3} \times \dfrac{22}{7} \times (3.5)^3 \\[1em] = \dfrac{4}{3} \times 22 \times 0.5 \times (3.5)^2 \\[1em] = \dfrac{539}{3} \\[1em] = 179\dfrac{2}{3} \text{ cm}^3.

Hence, volume of sphere = 17923179\dfrac{2}{3} cm3.

(ii) By formula,

Volume of cube = (side)3

= 73

= 343 cm3.

Volume of wood left = Volume of cube - Volume of sphere

=34317923=3435393=10295393=4903 cm3.= 343 - 179\dfrac{2}{3} \\[1em] = 343 - \dfrac{539}{3} \\[1em] = \dfrac{1029 - 539}{3} \\[1em] = \dfrac{490}{3} \text{ cm}^3.

Percentage of wood wasted = Volume of wood leftVolume of wood×100\dfrac{\text{Volume of wood left}}{\text{Volume of wood}} \times 100

Solving,

4903343×1004901029×100490001029100021471321%.\Rightarrow \dfrac{\dfrac{490}{3}}{343} \times 100 \\[1em] \Rightarrow \dfrac{490}{1029} \times 100 \\[1em] \Rightarrow \dfrac{49000}{1029} \\[1em] \Rightarrow \dfrac{1000}{21} \\[1em] \Rightarrow 47\dfrac{13}{21} \%.

Hence, percentage of wood wasted = 47132147\dfrac{13}{21} %.

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