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Physics

A train moving with a velocity of 20 m s-1 is brought to rest by applying brakes in 5 s. Calculate the retardation.

Motion in One Dimension

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Answer

According to equation of motion —

v = u + at

Given,

u = 20 m s-1,

v = 0,

t = 5 s

Substituting the values in the formula above, we get,

0=(20)+(a×5)0=20+5a⇒−20=5a⇒a=−205⇒a=−4ms−20 = (20) + (a \times 5) \\[0.5em] 0 = 20 + 5a \\[0.5em] \Rightarrow -20 = 5a \\[0.5em] \Rightarrow a = -\dfrac{20}{5} \\[0.5em] \Rightarrow a = - 4 ms^{-2}\\[0.5em]

Hence, Retardation is 4 m s-2

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