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Physics

A bullet initially moving with a velocity 20 m s-1 strikes a target and comes to rest after penetrating a distance 10 cm in the target. Calculate the retardation caused by the target.

Motion in One Dimension

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Answer

According to equation of motion —

v2 = u2 + 2aS

Given,

u = 20 m s-1,

v = 0,

s = 10 cm = 0.1 m

Substituting the values in the formula above, we get,

0=(20)2+(2×a×0.1)⇒0=400+0.2a⇒−400=0.2a⇒a=−4000.2⇒a=−40002⇒a=−2000ms−20 = (20)^2 + (2\times a \times 0.1) \\[0.5em] \Rightarrow 0 = 400 + 0.2 a \\[0.5em] \Rightarrow -400 = 0.2a \\[0.5em] \Rightarrow a = -\dfrac{400}{0.2} \\[0.5em] \Rightarrow a = -\dfrac{4000}{2} \\[0.5em] \Rightarrow a = - 2000 ms^{-2}\\[0.5em]

Hence, Retardation is 2000 m s-2

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