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Mathematics

A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the cone so formed. (Take π = 3.14)

Mensuration

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Answer

Since, triangle is revolved about 8 cm side so,

h = 8 cm, r = 6 cm and l = 10 cm.

Volume of cone = 13πr2h\dfrac{1}{3}πr^2h

Putting values in equation we get,

Volume of cone = 13×3.14×(6)2×8\dfrac{1}{3} \times 3.14 \times (6)^2 \times 8

= 904.323\dfrac{904.32}{3}

= 301.44 cm3.

Curved surface area = πrl.

Putting values in equation we get,

Curved surface area = 3.14 × 6 × 10 = 188.4 cm2.

Hence, the volume of cone = 301.44 cm3 and curved surface area = 188.4 cm2.

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