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A ray of light incident at an angle of incidence 48° on a prism of refracting angle 60° suffers minimum deviation. Calculate the angle of minimum deviation. [ Hint — δmin = 2i - A ]

Refraction Plane Surfaces

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Answer

As we know,

δmin=2iAδ_ {min} = 2i - A

Given,

i = 48°

A = 60°

So, substituting the values in the formula above we get,

δmin=(2×48°)60°δmin=96°60°δmin=36°δ_ {min} = (2 \times 48°) - 60° \\[0.5em] δ_ {min} = 96° - 60° \\[0.5em] \Rightarrow δ_ {min} = 36° \\[0.5em]

Hence, the angle of minimum deviation is equal to 36°

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