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What should be the angle of incidence for a ray of light which suffers minimum deviation of 36° through an equilateral prism?[ Hint — A = 60° and i = ( A + δmin ) / 2 ]

Refraction Plane Surfaces

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Answer

As we know,

δmin=2iAδ_{min} = 2i - A

Given,

δmin=36°δ_{min} = 36°

A = 60°

So, substituting the values in the formula above we get,

36°=(2×i)60°i=(36°+60°)2i=962i=48°36° = (2 \times i) - 60° \\[0.5em] \Rightarrow i = \dfrac{(36° + 60°)}{2} \\[0.5em] \Rightarrow i = \dfrac{96}{2} \\[0.5em] \Rightarrow i = 48° \\[0.5em]

Hence, the angle of incidence is equal to 48°.

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