A body, initially at rest, starts moving with a constant acceleration 2 m s ^-2.

Calculate —

(i) the velocity acquired and

(ii) and the distance travelled in 5 s.

As we know, from the equation of motion,

v = u + at

Given,

a = 2 m s ^-2

u = 0

t = 5 s

Substituting the values in the formula, we get,

$v = 0 + (2 ms^{-2} \times 5 s) \\[0.5em] v = 10 ms^{-1} \\[0.5em]$

Hence, the velocity acquired = 10 m s^-1

(ii) According to equation of motion —

S = ut + $\dfrac{1}{2}$ at²

Substituting the values in the formula, we get,

$S = (0 \times 5) + (\dfrac{1}{2} \times 2 \times 5^2) \\[0.5em] S = 0 + (\dfrac{1}{2} \times 2 \times 5^2) \\[0.5em] \Rightarrow S = 0 + (\dfrac{1}{2} \times 2 \times 25) \\[0.5em] \Rightarrow S = 0 + 25$

Hence, distance travelled = 25 m