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Physics

A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20ms-1. Calculate the maximum potential energy it gains as it goes up.

Work, Energy & Power

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Answer

Given,

Mass = 0.20 kg

Initial velocity = 20ms-1

We know,

KE=12×m×v2KE = \dfrac{1}{2} \times m \times v^2

Maximum potential energy at the maximum height = initial kinetic energy

Substituting the values in the equation

KE=12×0.20×202KE=12×0.20×400KE = \dfrac{1}{2} \times 0.20 \times 20^2 \\[0.5em] KE = \dfrac{1}{2} \times 0.20 \times 400

∴ Maximum potential energy at the maximum height = Initial kinetic energy = 40 J

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