Write the first four terms of the A.P. when its first term is -5 and common difference is -3.

Given, a = -5 and d = -3.

We know that

   a_n = a + (n - 1)d
∴ a₂ = -5 + (2 - 1) × (-3) = -5 + (-3) = -5 - 3 = -8.
   a₃ = -5 + (3 - 1) × (-3) = -5 + 2 × -3 = -5 - 6 = -11.
   a₄ = -5 + (4 - 1) × (-3) = -5 + 3 × -3 = -5 - 9 = -14.

Hence, the first four terms of the A.P. are -5, -8, -11, -14.