Chemistry
Write balanced equation for the following reactions:
(i) Lead sulphate from lead nitrate solution and dilute sulphuric acid.
(ii) Copper sulphate from copper and conc. sulphuric acid.
Sulphuric Acid
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Answer
(i) Pb(NO3)2 + H2SO4 [dil] ⟶ PbSO4 + 2HNO3
(ii) Cu + 2H2SO4 [conc.] ⟶ CuSO4 + 2H2O + SO2
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Which property of sulphuric acid accounts for it's use as a dehydrating agent.
Conc. H2SO4 is an oxidizing agent and a non volatile acid. Write an equation for each property.
Properties of H2SO4 are listed below. Choose the property A, B, C or D which is responsible for the reactions (i) to (v).
A : Acid
B: Dehydrating agent
C: Non-volatile acid
D: Oxidizing agent(i) C12H22O11+ nH2SO4 ⟶ 12C + 11H2O + nH2SO4
(ii) S + 2H2SO4 ⟶ 3SO2 + 2H2O
(iii) NaCl + H2SO4 ⟶ NaHSO4 + HCl
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