Chemistry
Dilute hydrochloric acid and dilute sulphuric acid are both colourless solutions. How will the addition of barium chloride solution to each help to distinguish between the two.
Sulphuric Acid
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Answer
Barium chloride soln. reacts with dilute sulphuric acid to give a white ppt. of barium sulphate (BaSO4) but with dil. HCl no white ppt. is produced.
H2SO4 (dil.) + BaCl2 (aq.) ⟶ 2HCl + BaSO4 ↓ [white ppt. formed]
HCl (dil.) + BaCl2 (aq.) ⟶ no reaction
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Related Questions
Write balanced equation for the following reactions:
(i) Lead sulphate from lead nitrate solution and dilute sulphuric acid.
(ii) Copper sulphate from copper and conc. sulphuric acid.
Properties of H2SO4 are listed below. Choose the property A, B, C or D which is responsible for the reactions (i) to (v).
A : Acid
B: Dehydrating agent
C: Non-volatile acid
D: Oxidizing agent(i) C12H22O11+ nH2SO4 ⟶ 12C + 11H2O + nH2SO4
(ii) S + 2H2SO4 ⟶ 3SO2 + 2H2O
(iii) NaCl + H2SO4 ⟶ NaHSO4 + HCl
(iv) CuO + H2SO4 ⟶ CuSO4 + H2O
(v) Na2CO3 + H2SO4 ⟶Na2SO4 + H2O + CO2
(Some properties may be repeated)
From HCl, HNO3, H2SO4 state which has the highest boiling point and which has the lowest.
Dilute H2SO4 will produce a white ppt. when added to a solution of:
A. Copper nitrate
B. Zinc nitrate
C. Lead nitrate
D. Sodium nitrate