Computer Applications
Write a program to input a three digit number. Use a method int Armstrong(int n) to accept the number. The method returns 1, if the number is Armstrong, otherwise zero(0).
Sample Input: 153
Sample Output: 153 ⇒ 13 + 53 + 33 = 153
It is an Armstrong Number.
Answer
import java.util.Scanner;
public class KboatArmstrongNumber
{
public int armstrong(int n) {
int num = n, cubeSum = 0;
while (num > 0) {
int digit = num % 10;
cubeSum = cubeSum + (digit * digit * digit);
num /= 10;
}
if (cubeSum == n)
return 1;
else
return 0;
}
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
System.out.print("Enter Number: ");
int num = in.nextInt();
KboatArmstrongNumber obj = new KboatArmstrongNumber();
int r = obj.armstrong(num);
if (r == 1)
System.out.println(num + " is an Armstrong number");
else
System.out.println(num + " is not an Armstrong number");
}
}Variable Description Table
Program Explanation
Output
Related Questions
Write a program to input a number and check and print whether it is a 'Pronic' number or not. Use a method int Pronic(int n) to accept a number. The method returns 1, if the number is 'Pronic', otherwise returns zero (0).
(Hint: Pronic number is the number which is the product of two consecutive integers)Examples:
12 = 3 * 4
20 = 4 * 5
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Sample Input:
Printed price: ₹12000
Successive discounts = 10%, 8%
= ₹(12000 - 1200)
= ₹(10800 - 864)
Amount to be paid = ₹9936Write a program to enter a two digit number and find out its first factor excluding 1 (one). The program then find the second factor (when the number is divided by the first factor) and finally displays both the factors.
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The first factor of 21 is 3
Sample Output: 3, 7
Sample Input: 30
The first factor of 30 is 2
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S = n! / (m!(n - m)!)
where, n! = 1 x 2 x 3 x ………. x n