In the adjoining figure, AB = AC and AD is median of △ABC, then ∠ADC is equal to

1. 60°

2. 120°

3. 90°

4. 75°

In the adjoining figure, O is the mid-point of AB. If ∠ACO = ∠BDO, then ∠OAC is equal to

1. ∠OCA

2. ∠ODB

3. ∠OBD

4. ∠BOD

In the adjoining figure, AB = FC, EF = BD and ∠AFE = ∠CBD. Then the rule by which △AFE ≅ △CBD is

1. SAS

2. ASA

3. SSS

4. AAS

In the adjoining figure, AB ⊥ BE and FE ⊥ BE. If AB = FE and BC = DE, then

1. △ABD ≅ △EFC

2. △ABD ≅ △FEC

3. △ABD ≅ △ECF

4. △ABD ≅ △CEF