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In the adjoining figure, AB ⊥ BE and FE ⊥ BE. If AB = FE and BC = DE, then

  1. △ABD ≅ △EFC

  2. △ABD ≅ △FEC

  3. △ABD ≅ △ECF

  4. △ABD ≅ △CEF

In the adjoining figure, AB ⊥ BE and FE ⊥ BE. If AB = FE and BC = DE, then? Triangles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

Triangles

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Answer

In △ABD and △FEC,

Given,

⇒ BC = ED

⇒ BC + CD = ED + CD

⇒ BD = EC.

AB = FE (Given)

∠ABD = ∠FEC (Both are equal to 90°)

Hence, △ABD ≅ △FEC by SAS axiom.

Hence, Option 2 is the correct answer.

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