Mathematics
In the adjoining figure, AB ⊥ BE and FE ⊥ BE. If AB = FE and BC = DE, then
△ABD ≅ △EFC
△ABD ≅ △FEC
△ABD ≅ △ECF
△ABD ≅ △CEF
Triangles
ICSE
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Answer
In △ABD and △FEC,
Given,
⇒ BC = ED
⇒ BC + CD = ED + CD
⇒ BD = EC.
AB = FE (Given)
∠ABD = ∠FEC (Both are equal to 90°)
Hence, △ABD ≅ △FEC by SAS axiom.
Hence, Option 2 is the correct answer.
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