Mathematics
What point on x-axis is equidistant from the points (6, 7) and (4, -3) ?
Section Formula
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Answer
We know that,
y-coordinate on x-axis = 0.
Let the point on x-axis be (x, 0).
Distance formula = 2 - x1)^2 + (y2 - y1)^2}
Since, (x, 0) is equidistant from (6, 7) and (4, -3)
Squaring both sides we get :
(x, 0) = (15, 0).
Hence, (15, 0) is equidistant from (6, 7) and (4, -3).
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