KnowledgeBoat Logo

Mathematics

Find the sum of n terms of the sequence : 5 + 55 + 555 + …….

AP GP

1 Like

Answer

Given,

Sequence : 5 + 55 + 555 + …….

⇒ 5(1 + 11 + 111 + ……..)

59×9(1+11+111+.........\dfrac{5}{9} \times 9(1 + 11 + 111 + ……… upto n terms)

59(9+99+999+.........\dfrac{5}{9}(9 + 99 + 999 + ……… upto n terms)

59[(101)+(1021)+(1031)+.......\dfrac{5}{9}[(10 - 1) + (10^2 - 1) + (10^3 - 1) + ……. upto n terms]

59[(10+102+103+ upto n terms)n]\dfrac{5}{9}[(10 + 10^2 + 10^3 + \text{ upto n terms}) - n]

59[(10(10n1)101n)]\dfrac{5}{9}\Big[\Big(\dfrac{10(10^n - 1)}{10 - 1} - n\Big)\Big]

59×10(10n1)959n\dfrac{5}{9} \times \dfrac{10(10^n - 1)}{9} - \dfrac{5}{9}n

50(10n1)8159n\dfrac{50(10^n - 1)}{81} - \dfrac{5}{9}n

Hence, sum = 50(10n1)8159n\dfrac{50(10^n - 1)}{81} - \dfrac{5}{9}n.

Answered By

1 Like


Related Questions