Mathematics
Using the information in the given diagram, state if :
AD = DC
BD = DC
CD bisects angle ACB
angle CAD is greater than angle DAB
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Answer
From figure,
AD = DB = AC = BC = x (let)
In △ ADC and △ BDC,
⇒ AD = DB (Both equal to x)
⇒ AC = BC (Both equal to x)
⇒ CD = CD (Common side)
∴ △ ADC ≅ △ BDC (By S.S.S. axiom)
We know that,
Corresponding parts of congruent triangle are equal.
∴ ∠ACD = ∠BCD
∴ CD bisects angle ACB.
Hence, Option 3 is the correct option.
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Bisector of angle B of triangle ABC intersects side AC at point P, then point P is :
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Given: PQ is a perpendicular bisector of side AB of the triangle ABC.
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