Mathematics
P is a point on bisector of angle A of △ABC. Then:
P is equidistant from the vertices B and C
PA = PC
PA = PB
P is equidistant from sides AB and AC of the △ABC.
Locus
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Answer
We know that,
The locus of a point equidistant from two intersecting lines is the bisector of the angles between the lines.
Given,
P is a point on bisector of angle A of △ABC.
∴ P is equidistant from sides AB and AC of the △ABC.
Hence, Option 4 is the correct option.
Answered By
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Related Questions
The perpendicular bisector of side AB and bisector of angle A of △ABC meet at point P. Then :
PA = PB
PA = PC
PB = PC
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Using the information in the given diagram, state if :
AD = DC
BD = DC
CD bisects angle ACB
angle CAD is greater than angle DAB
Bisector of angle B of triangle ABC intersects side AC at point P, then point P is :
equidistant from vertices A and C
PA = PB
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equidistant from sides AB and BC
P is a point on perpendicular bisector of side BC of △ABC, then :
PA = PB
PB = PC
PA = PC
none of these