Mathematics
Using a graph paper, plot the points A(6, 4) and B(0, 4).
(i) Reflect A and B in the origin to get images A' and B'.
(ii) Write the coordinates of A' and B'.
(iii) State the geometrical name for the figure ABA'B'.
(iv) Find its perimeter.
Reflection
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Answer
(i) A' and B' are plotted on the graph below:
(ii) From graph we get,
The coordinates of A' and B' are (-6, -4) and (0, -4) respectively.
(iii) From graph we get,
ABA'B' formed is a parallelogram.
(iv) From graph we get,
By pythagoras theorem,
Perimeter = Sum of all sides = AB' + B'A' + A'B + BA = 10 + 6 + 6 + 10 = 32 units.
Hence, the perimeter of the parallelogram is 32 units.
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(i) Plot the points A(4, 6) and B(1, 2).
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(iii) If B' is the image of B when reflected in the line AA', write the coordinates of B'.
(iv) Give the geometrical name for the figure ABA'B'.
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