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Mathematics

Use graph paper for this question.

(i) The point P(2, -4) is reflected about the line x = 0 to get the image Q. Find the coordinates of Q.

(ii) Point Q is reflected about the line y = 0 to get the image R. Find the coordinates of R.

(iii) Name the figure PQR.

(iv) Find the area of the figure PQR.

Reflection

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Answer

The graph is given below:

Use graph paper for this question. (i) The point P(2, -4) is reflected about the line x = 0 to get the image Q. Find the coordinates of Q. (ii) Point Q is reflected about the line y = 0 to get the image R. Find the coordinates of R. (iii) Name the figure PQR. (iv) Find the area of the figure PQR. Reflection, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

(i) From graph we get,

The coordinate of Q is (-2, -4).

(ii) From graph we get,

The coordinate of R is (-2, 4).

(iii) From graph we get,

The image formed is right angled triangle.

(iv) We know that in the graph,

One block represents 1 unit.

Area of right angle triangle = 12×\dfrac{1}{2} \times base × height.

=12×PQ×QR=12×4 units ×8 units =16 sq. units.= \dfrac{1}{2} \times \text{PQ} \times \text{QR} \\[1em] = \dfrac{1}{2} \times 4 \text{ units } \times 8 \text{ units } \\[1em] = 16 \text{ sq. units}.

Hence, the area of figure PQR is 16 sq. units.

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