In the given figure,

AB = 10 cm, CD = 8 cm = OB, then OD is equal to :

1. 10 cm

2. 3.2 cm

3. 6.4 cm

4. 8 cm

In the given figure, AE : EC = 2 : 3 and BC = 20 cm then DE is equal to :

1. 10 cm

2. 12 cm

3. 8 cm

4. 16 cm

In the following figure, point D divides AB in the ratio 3 : 5. Find:

(i) $\dfrac{\text{AE}}{\text{EC}}$

(ii) $\dfrac{\text{AD}}{\text{AB}}$

(iii) $\dfrac{\text{AE}}{\text{AC}}$

Also if,

(iv) DE = 2.4 cm, find the length of BC.

(v) BC = 4.8 cm, find the length of DE.

In the given figure, PQ || AB; CQ = 4.8 cm, QB = 3.6 cm and AB = 6.3 cm. Find :

(i) $\dfrac{CP}{PA}$

(ii) PQ

(iii) If AP = x, then the value of AC in terms of x.