Physics
Three resistors Of 5 Ω, 10 Ω and 15 Ω are connected in series with a 12 V power supply.
(a) Calculate their combined resistance and the current that flows in the circuit and in each resistor.
(b) Find the potential difference across each resistor.
Current Electricity
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Answer
(a) In the circuit 5 Ω, 10 Ω and 15 Ω are connected in series. If the equivalent resistance of this part is Rs then
Rs = 5 + 10 + 15 = 30 Ω
According to Ohm's law: V = IR
Substituting the values in the formula:
12 = I x 30
I = = 0.4 A
Hence, combined resistance = 30 Ω and current flowing in the circuit = 0.4 A
As in a series circuit current flowing through each resistor is equal to the total current flowing in the circuit, hence, current flowing through each resistor = 0.4 A
(b) Potential difference across 5 Ω resistor: ?
Applying Ohm's law: V = IR
Substituting the values in the formula:
V = 0.4 x 5 = 2 V
Potential difference across 10 Ω resistor: ?
V = 0.4 x 10 = 4 V
Potential difference across 15 Ω : ?
V = 0.4 x 15 = 6 V
Hence, potential difference across 5 Ω resistor = 2, 10 Ω resistor = 4V, 15 Ω resistor = 6V
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