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Physics

The time period of two pendulums of length 1 m and 16 m are in ratio :

  1. 1 : 16
  2. 1 : 4
  3. 16 : 1
  4. 4 : 1

Measurements

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Answer

1 : 4

Reason — As, T ∝ l\sqrt{l}

T1T2\dfrac{T1}{T2} = l1l2\dfrac{\sqrt{l1}}{\sqrt{l2}}

T1T2\dfrac{T1}{T2} = 116\dfrac{\sqrt{1}}{\sqrt{16}}

T1T2\dfrac{T1}{T2} = 14\dfrac{1}{4}

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