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Physics

Time period of a simple pendulum is given by :

  1. T=2πglT = 2 π \sqrt{\dfrac{g}{l}}
  2. T=2πlgT = 2 π \sqrt{\dfrac{l}{g}}
  3. T=4πlgT = 4 π \sqrt{\dfrac{l}{g}}
  4. T=4πglT = 4 π \sqrt{\dfrac{g}{l}}

Measurements

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Answer

T=2πlgT = 2 π \sqrt{\dfrac{l}{g}}

Reason — Time period of a simple pendulum is given by T=2πlgT = 2 π \sqrt{\dfrac{l}{g}}

where

T = time period
l = effective length of pendulum
g = acceleration due to gravity.

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