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The surface area of a solid sphere is 1256 cm2. It is cut into two hemispheres. Find the total surface area and the volume of a hemisphere. Take π = 3.14

Mensuration

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Answer

Given,
surface area of the sphere = 1256 cm2.

We know that, surface area of sphere = 4πr2.

∴ 4πr2 = 1256

4×3.14×r2=1256r2=12563.14×4r2=125612.56r2=100r=100r=10 cm.\Rightarrow 4 \times 3.14 \times r^2 = 1256 \\[1em] \Rightarrow r^2 = \dfrac{1256}{3.14 \times 4} \\[1em] \Rightarrow r^2 = \dfrac{1256}{12.56} \\[1em] \Rightarrow r^2 = 100 \\[1em] \Rightarrow r = \sqrt{100} \\[1em] \Rightarrow r = 10 \text{ cm}.

Total surface area of hemisphere = 3πr2.

Putting values we get,

Total surface area of hemisphere = 3×3.14×(10)23 \times 3.14 \times (10)^2

=3×3.14×100=942 cm2.= 3 \times 3.14 \times 100 \\[1em] = 942 \text{ cm}^2.

Volume of hemisphere = 23πr3\dfrac{2}{3}πr^3.

Volume of hemisphere = 23×3.14×103\dfrac{2}{3} \times 3.14 \times 10^3

=23×3.14×1000=62803=209313cm3.= \dfrac{2}{3} \times 3.14 \times 1000 \\[1em] = \dfrac{6280}{3} \\[1em] = 2093\dfrac{1}{3} \text{cm}^3.

Hence, the surface area of hemisphere = 942 cm2 and volume of hemisphere = 209313 cm3.2093\dfrac{1}{3}\text{ cm}^3.

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