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The sound from a mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. What is the time period of the vibration?

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Answer

Given,

Total number of vibrations = 500

Total time taken = 1 s

We know,

Time period = 1Frequency\dfrac{1}{\text{Frequency}} and

Frequency = Total number of oscillationsTotal time taken\dfrac{\text{Total number of oscillations}}{\text{Total time taken}}

Hence,

Time period = Total time takenTotal number of oscillations \dfrac{\text{Total time taken}}{\text{Total number of oscillations }}

Substituting we get,

Time period = 1500\dfrac{1}{500} = 0.002 s

So, time period = 0.002 s.

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