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A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.

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Answer

Given,

Total number of oscillations = 40

Total time taken = 4 s

We know,

Frequency = Total number of oscillationsTotal time taken\dfrac{\text{Total number of oscillations}}{\text{Total time taken}}

Substituting we get,

Frequency = 404\dfrac{40}{4} = 10 Hz

Time period = 1Frequency\dfrac{1}{\text{Frequency}}

Substituting we get,

Time period = 110\dfrac{1}{10} = 0.1 s

Hence, frequency = 10 Hz and time period = 0.1 s.

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