Physics

The pressure of water on the ground floor is 40,000 Pa and on the first floor is 10,000 Pa. Find the height of the first floor.
(Take : density of water = 1000 kg m^-3, g = 10 m s^-2)

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(i) As we know,

Pressure due to water column of height h = h ρ g

Given,

density of water = 1000 kg m ^-3

g = 10 m s^-2

P_w on ground floor = 40,000 Pa

P_w on first floor Pwf = 10,000 Pa

In order to know the height of the first floor, let us calculate the difference in pressure

P = P_wg - P_wf = 40,000 – 10,000 = 30,000 Pa

Substituting the values in the formula,

$P = h ρ g \\[0.5em] 30,000 = 1000 \times 10 \times h \\[0.5em] h = 3 m \\[0.5em]$

Hence, the height of the first floor = 3 m.

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