The point of intersection of the lines x + y = 8 and x - y = 0 lies on the line mx - 2y = 0; the value of m is : 1. 3 2. 4 3. 2 4. -2

Given, 1st Equation : ⇒ x + y = 8 ⇒ x = 8 - y ......(1) 2nd equation : ⇒ x - y = 0 ⇒ x = y .........(2) Substituting value of x from equation (2) in (1), we get : ⇒ y = 8 - y ⇒ y + y = 8 ⇒ 2y = 8 ⇒ y = = 4. From equation (2), we get : ⇒ x = y = 4. Point of intersection of lines x + y = 8 and x - y = 0 is (4, 4). Given, point of intersection lies on the line mx - 2y = 0. Substituting values we get : ⇒ 4m - 2 × 4 = 0 ⇒ 4m - 8 = 0 ⇒ 4m = 8 ⇒ m = = 2. Hence, Option 3 is the correct option.

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The line x + y = 4 bisects the line segment joining the points (0, k) and (4, 0), the value of k is :
2
4
-4
-2

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Find which of the following points lie on the line x - 2y + 5 = 0 :
(i) (1, 3)
(ii) (0, 5)
(iii) (-5, 0)
(iv) (5, 5)

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Mathematics

The point of intersection of the lines x + y = 8 and x - y = 0 lies on the line mx - 2y = 0; the value of m is :
3
4
2
-2

Straight Line Eq

Related Questions

The line x + y = 4 bisects the line segment joining the points (0, k) and (4, 0), the value of k is :
2
4
-4
-2

Find which of the following points lie on the line x - 2y + 5 = 0 :
(i) (1, 3)
(ii) (0, 5)
(iii) (-5, 0)
(iv) (5, 5)

Mathematics

The point of intersection of the lines x + y = 8 and x - y = 0 lies on the line mx - 2y = 0; the value of m is :342-2

Straight Line Eq

Related Questions

The line x + y = 4 bisects the line segment joining the points (0, k) and (4, 0), the value of k is :24-4-2

Find which of the following points lie on the line x - 2y + 5 = 0 :(i) (1, 3)(ii) (0, 5)(iii) (-5, 0)(iv) (5, 5)

The point of intersection of the lines x + y = 8 and x - y = 0 lies on the line mx - 2y = 0; the value of m is :
3
4
2
-2

The line x + y = 4 bisects the line segment joining the points (0, k) and (4, 0), the value of k is :
2
4
-4
-2

Find which of the following points lie on the line x - 2y + 5 = 0 :
(i) (1, 3)
(ii) (0, 5)
(iii) (-5, 0)
(iv) (5, 5)