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Mathematics

The line x + y = 4 bisects the line segment joining the points (0, k) and (4, 0), the value of k is :

  1. 2

  2. 4

  3. -4

  4. -2

Straight Line Eq

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Answer

Given,

Points : (0, k) and (4, 0)

By formula,

Mid-point : (x1+x22,y1+y22)\Big(\dfrac{x1 + x2}{2}, \dfrac{y1 + y2}{2}\Big)

Substituting values we get :

Mid-point =(0+42,k+02)=(42,k2)=(2,k2).\text{Mid-point } = \Big(\dfrac{0 + 4}{2}, \dfrac{k + 0}{2}\Big) \\[1em] = \Big(\dfrac{4}{2}, \dfrac{k}{2}\Big) \\[1em] = \Big(2, \dfrac{k}{2}\Big).

Given,

Line x + y = 4 bisects the line segment joining the points (0, k) and (4, 0).

∴ Line x + y = 4 passes through the point (2,k2)\Big(2, \dfrac{k}{2}\Big).

Substituting value we get :

2+k2=4k2=42k2=2k=4.\Rightarrow 2 + \dfrac{k}{2} = 4 \\[1em] \Rightarrow \dfrac{k}{2} = 4 - 2 \\[1em] \Rightarrow \dfrac{k}{2} = 2 \\[1em] \Rightarrow k = 4.

Hence, Option 2 is the correct option.

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