P is a point on perpendicular bisector of side BC of △ABC, then :

1. PA = PB

2. PB = PC

3. PA = PC

4. none of these

P is a point on bisector of angle A of △ABC. Then:

1. P is equidistant from the vertices B and C

2. PA = PC

3. PA = PB

4. P is equidistant from sides AB and AC of the △ABC.

Using the information in the given diagram, state if :

1. AD = DC

2. BD = DC

3. CD bisects angle ACB

4. angle CAD is greater than angle DAB

Bisector of angle B of triangle ABC intersects side AC at point P, then point P is :

1. equidistant from vertices A and C

2. PA = PB

3. PB = PC

4. equidistant from sides AB and BC