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Mathematics

The ordinate of a point lying on the line joining the points (6, 4) and (7, -5) is -23. Find the co-ordinates of that point.

Straight Line Eq

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Answer

Let point A = (6, 4) and B = (7, -5).

Let the point P be (a, -23).

By formula,

Slope = y2y1x2x1\dfrac{y2 - y1}{x2 - x1}

Slope of AB = 5476=91\dfrac{-5 - 4}{7 - 6} = \dfrac{-9}{1} = -9.

By point-slope form,

⇒ y - y1 = m(x - x1)

⇒ y - 4 = -9(x - 6)

⇒ y - 4 = -9x + 54

⇒ 9x + y = 54 + 4

⇒ 9x + y = 58.

Since, P lies on AB so it will satisfy the equation.

Substituting values of P in equation we get,

⇒ 9(a) + (-23) = 58

⇒ 9a - 23 = 58

⇒ 9a = 58 + 23

⇒ 9a = 81

⇒ a = 819\dfrac{81}{9}

⇒ a = 9.

∴ P = (a, -23) = (9, -23).

Hence, co-ordinates of the required point are (9, -23).

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