The median of 3, 8, 11, 2, 16, 4, 0 and 6 is :

1. 6

2. 9

3. 5

4. 8

Arranging the numbers in ascending order, we get :

0, 2, 3, 4, 6, 8, 11, 16.

The number of terms (n) are 8, which is even.

∴ Median = $\dfrac{\Big(\dfrac{n}{2}\Big) \text{ th term} + \Big(\dfrac{n}{2} + 1\Big)\text{ th term}}{2}$

Substituting values we get :

$\text{Median } = \dfrac{\Big(\dfrac{8}{2}\Big) \text{ th term} + \Big(\dfrac{8}{2} + 1\Big) \text{ th term}}{2} \\[1em] = \dfrac{\text{4 th term + 5 th term}}{2} \\[1em] = \dfrac{4 + 6}{2} \\[1em] = \dfrac{10}{2} \\[1em] = 5.$

Hence, Option 3 is the correct option.