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The mass of 1 cm3 of iron is 7.8 g, its density in S.I. unit is :

  1. 7.8 kg/cm3
  2. 7.8 g cm-3
  3. 7800 g/cm3
  4. 7800 kg/m3

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Answer

7800 kg/m3

Reason —

Density = massvolume\dfrac{\text{mass}}{\text{volume}} = 7.81\dfrac{7.8}{1} g/cm3

Converting g cm-3 into kg m-3,

We know, 1 g = 10-3 kg

1 cm = 10-2 m

1 cm3 = 10-6 m3

Therefore,

7.8 gcm3\dfrac{\text {g}}{\text {cm}^3}

= 7.8 103kg106m3\dfrac{10^{-3}\text {kg}}{10^{-6} \text{m}^3}

= 7.8 103kg1m3\dfrac{10^{3}\text {kg}}{1 \text{m}^3}

= 7.8 x 1000 kg m-3

Hence,

7.8 g/cm3 = 7800 kg/m3

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