Physics
A body of mass 3.5 kg displaces 1000 cm3 of water when fully immersed inside it. Calculate (i) the volume of body, (ii) the upthrust on body and (iii) the apparent weight of body in water.
Fluids Upthrust
50 Likes
Answer
Given,
Mass = 3.5 kg
Therefore, weight = 3.5 kgf
Volume of displaced water = 1000 cm3
(i) Volume of body = volume of the water displaced = 1000 cm3
Hence, the volume of body = 1000 cm3
(ii) Upthrust on body = volume of the body x density of water x g
= 1000 x 0.001 x g
= 1 kgf
(iii) The apparent weight of body in water = true weight – upthrust
= 3.5 - 1
= 2.5 kgf
Answered By
38 Likes
Related Questions
A metal cube of edge 5 cm and density 9.0 g cm-3 is suspended by a thread so as to be completely immersed in a liquid of density 1.2 g cm-3. Find the tension in thread. (Take g = 10 m s-2)
[Hint: Tension in thread = apparent weight of the cube in liquid]
A block of wood is floating on water with it's dimensions 50 cm x 50 cm x 50 cm inside water. Calculate the buoyant force acting on the block. Take g = 9.8 N kg-1.
The effect of temperature on density is that it :
- decreases with an increase in temperature
- increases with an increase in temperature
- first decreases then increases with a decrease in temperature
- is not affected by temperature
The density of copper is :
- 9.0 g cm-3
- 8.9 g cm-3
- 9.1 g cm-3
- 8.9 kg m-3