The height of the cone is 15 cm. If its volume is 1570 cm³, find the radius of the base. (Use π = 3.14)

We know,

Volume of cone = $\dfrac{1}{3}πr^2h$.

Given, Volume of cone = 1570 cm³ and h = 15 cm.

$\Rightarrow \dfrac{1}{3}πr^2h = 1570 \\[1em] \Rightarrow \dfrac{1}{3} \times 3.14 \times r^2 \times 15 = 1570 \\[1em] \Rightarrow r^2 = \dfrac{1570 \times 3}{15 \times 3.14} \\[1em] \Rightarrow r^2 = \dfrac{4710}{47.1} \\[1em] \Rightarrow r^2 = 100 \\[1em] \Rightarrow r = \sqrt{100} = 10 \text{ cm}.$

Hence, the radius of the base = 10 cm.