A conical tent is 10 m high and the radius of its base is 24 m. Find :

(i) slant height of the tent.

(ii) cost of the canvas required to make the tent, if the cost of 1 m² canvas is ₹ 70.

(i) Given r = 24 m and h = 10 m.

We know that,

$l = \sqrt{r^2 + h^2}$

Putting values in the formula we get,

$\Rightarrow l = \sqrt{(24)^2 + (10)^2} \\[1em] \Rightarrow l = \sqrt{576 + 100} \\[1em] \Rightarrow l = \sqrt{676} = 26 \text{ cm}.$

Hence, the slant height of the cone = 26 cm.

(ii) Curved surface area of cone = πrl.

Putting values in equation,

Curved surface area of tent = $\dfrac{22}{7} \times 24 \times 26 = \dfrac{13728}{7}$ m².

Cost of 1 m² of canvas = ₹ 70

∴ Cost of $\dfrac{13728}{7}$ m² of canvas = ₹ $\dfrac{13728}{7}$ × 70 = ₹ 137280.

Hence, the cost of canvas required to make tent = ₹ 137280.