Mathematics
The contents of 100 match boxes were checked to determine the number of matches they contained.
No. of matches | No. of boxes |
---|---|
35 | 6 |
36 | 10 |
37 | 18 |
38 | 25 |
39 | 21 |
40 | 12 |
41 | 8 |
(i) Calculate, correct to one decimal place, the mean number of matches per box.
(ii) Determine, how many extra matches would have to be added to the total contents of the 100 boxes to bring the mean up to exactly 39 matches ?
Measures of Central Tendency
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Answer
(i)
No. of matches (x) | No. of boxes (f) | fx |
---|---|---|
35 | 6 | 210 |
36 | 10 | 360 |
37 | 18 | 666 |
38 | 25 | 950 |
39 | 21 | 819 |
40 | 12 | 480 |
41 | 8 | 328 |
Total | 100 | 3813 |
By formula,
Mean = = 38.13 ≈ 38.1
Hence, mean = 38.1
(ii) By formula,
Mean =
If mean = 39.
No. of matches to add = 3900 - 3813 = 87.
Hence, 87 extra matches need to be added.
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