KnowledgeBoat Logo

Mathematics

The contents of 100 match boxes were checked to determine the number of matches they contained.

No. of matchesNo. of boxes
356
3610
3718
3825
3921
4012
418

(i) Calculate, correct to one decimal place, the mean number of matches per box.

(ii) Determine, how many extra matches would have to be added to the total contents of the 100 boxes to bring the mean up to exactly 39 matches ?

Measures of Central Tendency

26 Likes

Answer

(i)

No. of matches (x)No. of boxes (f)fx
356210
3610360
3718666
3825950
3921819
4012480
418328
Total1003813

By formula,

Mean = ΣfxΣf=3813100\dfrac{Σfx}{Σf} = \dfrac{3813}{100} = 38.13 ≈ 38.1

Hence, mean = 38.1

(ii) By formula,

Mean = No. of matchesNo. of boxes\dfrac{\text{No. of matches}}{\text{No. of boxes}}

If mean = 39.

39=No. of matches100No. of matches=3900\Rightarrow 39 = \dfrac{\text{No. of matches}}{100} \\[1em] \Rightarrow \text{No. of matches} = 3900

No. of matches to add = 3900 - 3813 = 87.

Hence, 87 extra matches need to be added.

Answered By

17 Likes


Related Questions