The coordinates of the point which is equidistant from the three vertices of △AOB (shown in the adjoining figure) are

1. (x, y)

2. (y, x)

3. $\Big(\dfrac{x}{2}, \dfrac{y}{2}\Big)$

4. $\Big(\dfrac{y}{2}, \dfrac{x}{2}\Big)$

The fourth vertex D of a parallelogram ABCD whose vertices are A(-2, 3), B(6, 7) and C(8, 3) is

1. (0, 1)

2. (0, -1)

3. (-1, 0)

4. (1, 0)

The point which lies on the perpendicular bisector of the line segment joining the points A(-2, -5) and B(2, 5) is

1. (0, 0)

2. (0, 2)

3. (2, 0)

4. (-2, 0)

The point which divides the line segment joining the points (7, -6) and (3, 4) in the ratio 1 : 2 internally lies in the

1. Ist quadrant

2. IInd quadrant

3. IIIrd quadrant

4. IVth quadrant