The coordinates of the point which is equidistant from the three vertices of △AOB (shown in the adjoining figure) are

1. (x, y)

2. (y, x)

3. $\Big(\dfrac{x}{2}, \dfrac{y}{2}\Big)$

4. $\Big(\dfrac{y}{2}, \dfrac{x}{2}\Big)$

The point which divides the line segment joining the points (7, -6) and (3, 4) in the ratio 1 : 2 internally lies in the

1. Ist quadrant

2. IInd quadrant

3. IIIrd quadrant

4. IVth quadrant

The point which lies on the perpendicular bisector of the line segment joining the points A(-2, -5) and B(2, 5) is

1. (0, 0)

2. (0, 2)

3. (2, 0)

4. (-2, 0)

The fourth vertex D of a parallelogram ABCD whose vertices are A(-2, 3), B(6, 7) and C(8, 3) is

1. (0, 1)

2. (0, -1)

3. (-1, 0)

4. (1, 0)