The base of a right angled triangle is 12 cm and its hypotenuse is 13 cm long. Find its area and the perimeter.

It is given that, ABC is a right angled triangle. From figure, BC = 12 cm and AC = 13 cm Using the Pythagoras theorem, AC 2 = AB 2 + BC 2 Substituting the values we get, ⇒ 13 2 = AB 2 + 12 2 ⇒ AB 2 = 13 2 – 12 2 ⇒ AB 2 = 169 – 144 = 25 ⇒ AB = = 5 cm. We know that, Area of triangle ABC = × base × height. Substituting the values we get, A = = 30 cm 2 . Perimeter of triangle ABC (P) = AB + BC + CA Substituting the values we get, = 5 + 12 + 13 = 30 cm. Hence, area of triangle = 30 cm 2 and perimeter = 30 cm.

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Mathematics

The base of a right angled triangle is 12 cm and its hypotenuse is 13 cm long. Find its area and the perimeter.

Mensuration

Related Questions

The sides of a triangular field are 975 m, 1050 m and 1125 m. If this field is sold at the rate of ₹ 1000 per hectare, find its selling price.

Find the area of an equilateral triangle whose side is 8 m. Give your answer correct to two decimal places.

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