The base of a right angled triangle is 12 cm and its hypotenuse is 13 cm long. Find its area and the perimeter.

It is given that, ABC is a right angled triangle. From figure, BC = 12 cm and AC = 13 cm Using the Pythagoras theorem, AC 2 = AB 2 + BC 2 Substituting the values we get, ⇒ 13 2 = AB 2 + 12 2 ⇒ AB 2 = 13 2 – 12 2 ⇒ AB 2 = 169 – 144 = 25 ⇒ AB = = 5 cm. We know that, Area of triangle ABC = × base × height. Substituting the values we get, A = = 30 cm 2 . Perimeter of triangle ABC (P) = AB + BC + CA Substituting the values we get, = 5 + 12 + 13 = 30 cm. Hence, area of triangle = 30 cm 2 and perimeter = 30 cm.

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Mathematics

The base of a right angled triangle is 12 cm and its hypotenuse is 13 cm long. Find its area and the perimeter.

Mensuration

Related Questions

Find the area of an equilateral triangle whose side is 8 m. Give your answer correct to two decimal places.

The sides of a triangular field are 975 m, 1050 m and 1125 m. If this field is sold at the rate of ₹ 1000 per hectare, find its selling price.

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