The 10th term of the A.P. 5, 8, 11, 14, …. is
32
35
38
185
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The above series is an A.P. with first term = a = 5 and common difference = d = 8 - 5 = 3.
We know that
an = a + (n - 1)d∴ a10 = 5 + (10 - 1) × 3 = 5 + 9 × 3 = 5 + 27 = 32.
Hence, Option 1 is the correct option.
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Find the third term of a G.P. whose common ratio is 3 and the sum of whose first seven terms is 2186.
The 30th term of the A.P. 10, 7, 4, … is
87
77
-77
-87