The 11th term of the A.P. $-3, -\dfrac{1}{2}, 2, …$ is

1. 28

2. 22

3. -38

4. $-48\dfrac{1}{2}$

The above series is an A.P. with first term = a = -3 and common difference = $-\dfrac{1}{2} - (-3) = -\dfrac{1}{2} + 3 = -\dfrac{-1 + 6}{2} = \dfrac{5}{2}$.

We know that

a_n = a + (n - 1)d

$\therefore a_{11} = -3 + (11 - 1) \times \dfrac{5}{2} \\[1em] = -3 + 10 \times \dfrac{5}{2} \\[1em] = -3 + 25 \\[1em] = 22.$

Hence, Option 2 is the correct option.